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One mass m is suspended from a spring. Time period of oscilation is T. now if spring is divided into n pieces & these are joined in parallel order then time period of oscillation if same mass is suspended.A. `2pisqrt((n^(2)m)/k)`B. `2pisqrt((n^(2)k)/m)`C. `2pisqrt(m/(n^(2)k))`D. `2pisqrt(k/(n^(2)m))` |
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Answer» Correct Answer - C `T=2pisqrt(m/k)` And spring is devided into n piece and connected in parallel combination then `k_(eq)=n^(2)xxk` So new time period `=2pisqrt(m/(n^(2)k))` |
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