1.

One millimole of C_aSO_4 weighs _______ . (Ca = 40, S = 32, O = 16)

Answer»

136 G
13.6 g
0.136 g
0.0136 g

Solution :ONE mole of `CaSO_4`
= gram molecular weight of `CaSO_4`
= 40 + 32 + 64 = 136 g
One millimole of `CaSO_4` `= 136xx10^(-3) = 0.136 g`


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