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One mole a gas absorbs 1.2 kJ of heat at constant volume and its temperature is raised from 298 K to 328 K. The values of q, w and ∆u are respectively(1) ∆u = q = 1.2 kJ, w = 0 (2) ∆u = 0, q = w = 1.2 kJ (3) ∆u = 0, q = 1.2 kJ, w = − 1.2 kJ (4) ∆u = w = 1.2 kJ, q = 0 |
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Answer» Correct option (1) ∆u = q = 1.2 kJ, w = 0 Explanation: At constant volume, ∆u = 0, no work is done, the entire heat absorbed increases heat content of the system. |
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