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InterviewSolution
| 1. |
One mole a gas absorbs 1.2 kJ of heat at constant volume and its temperature is raised from 298 K to 328 K. The values of q, w and ∆u are respectively(1) ∆u = q = 1.2 kJ, w = 0 (2) ∆u = 0, q = w = 1.2 kJ (3) ∆u = 0, q = 1.2 kJ, w = − 1.2 kJ (4) ∆u = w = 1.2 kJ, q = 0 |
| Answer» <p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Correct option (1) ∆u = q = 1.2 kJ, w = 0</strong></span></span></p><p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Explanation:</strong> </span></span></p><p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif">At constant volume, ∆u = 0, no work is done, the entire heat absorbed increases heat content of the system.</span></span></p> | |