1.

One mole each of a monoatomic, diatomic and triatomic gases are mixed C_(p)//C_(v) for the mixture is

Answer»

`1.40`
1.428
1.67
None of these

Solution :`C_(v) = (((3)/(2) R + (5)/(2) R + (6)/(2)R))/(3) = (7R)/(3)`
`C_(p) = (((5)/(2) R + (7)/(2) R + (8)/(2) R))/(3) = (10R)/(3)`
`(C_(p))/(C_(v)) = (10)/(7) = 1.428`


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