One mole of A (g) is heated to 200^@ C in a one litre closed flask, till the following equilibrium is reached.A(g) leftrightarrow B(g)The rate of forward reaction, at equilibrium, is 0.02mol L^(-1) mi n^(-1). What is the rate (inmol L^(-1)mi n^(-1)) of the backward reaction at equilibrium?

One mole of A (g) is heated to 200^@ C in a one litre closed flask, ti

1.	One mole of A (g) is heated to 200^@ C in a one litre closed flask, till the following equilibrium is reached.A(g) leftrightarrow B(g)The rate of forward reaction, at equilibrium, is 0.02mol L^(-1) mi n^(-1). What is the rate (inmol L^(-1)mi n^(-1)) of the backward reaction at equilibrium?
Answer» Solution : `[B]=x=0.5 implies [A]=0.5` `K=(K_(f))/(K_(b))=(0.5)/(0.5)=1` `implies K_(b)=K_(f)=0.02=2xx10^(-2)`