1.

One mole of a gas expands by 3L against a constant pressure of 3 atmosphere. Calculate the work done in : (a) L. atmosphere (b) Joules (c) Calories

Answer»


Solution :Given :Number ofthemoles ofa GAS= n= 1 mol
volume ofexpansion = `Delta V = 3 L`
Constantpressure`=P _(EX)=3 atm`
Work(w) = ?in L atm, Joulesand Calories
`(a) W =- P_(ex) xxDelta V`
`=- 3XX 3`
=- 9.0 L atm
(b) :' 1 L atm= 101 .3 J
`:' W=- 90xx 101 .3 J`
=- 911.7 J
(c ):' 4.184 J = 1 cal
`:' W = (-911.7)/(4.184)`
=-217. 9cal


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