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One mole of a monoatomic ideal gas undergoes the process A rarr B in the given P-V diagram. What is the specific heat for this process ? |
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Answer» Solution :Specific heat `C= (DELTAQ)/(DeltaT)=1/(DeltaT)(DeltaU+W)=C_(v)+W/(DeltaT)` For the GIVEN process `W=4V_(0)(9P_(0))/2=18P_(0)V_(0)` `( :. W="area of "P-V" GRAPH")" Also", DeltaT=T_(2)-T_(1)` `=((6P_(0))(5V_(0)))/R-((3P_(0))V_(0))/R=(27P_(0)V_(0))/R and C_(v)=3/2R` `:. C=C_(v)+W/(DeltaT)=(3R)/2+(18P_(0)V_(0))/([(27P_(0)V_(0))/R]` `=(3R)/2+(2R)/3=(13R)/6` |
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