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    				| 1. | One mole of an ideal diatomic gas undergoes a transition from A to B along a path AB as shown in (figure). The change in internal energy of the gas during the transition is `(gamma=3//5)` A. `- 20 kJ`B. `20 J`C. `- 12 kJ`D. `20 kJ` | 
| Answer» `T_(A) = (P_(A) V_(A))/(nR) , T_(B) = (P_(B) V_(B))/(nR)` `(Delta U)_(A rarr B) = nC_(V) Delta T = n. (5R)/(2) (T_(B) - T_(A))` `= (5 nR)/(2) ((P_(B) V_(B) - P_(A) V_(A))/(nR))` `= (5)/(2) (P_(B) V_(B) - P_(A) V_(A))` `= (5)/(2) (2 xx 6 - 5 xx 4) xx 10^(3) = - 20 kJ` | |