One mole of an ideal gas at 27^(@)C undergoes isothermal expansion reversible from a volume of 10 dm^(3) to a volume of 20 dm^(3). Calculate the work done on the gas.

One mole of an ideal gas at 27^(@)C undergoes isothermal expansion rev

1.	One mole of an ideal gas at 27^(@)C undergoes isothermal expansion reversible from a volume of 10 dm^(3) to a volume of 20 dm^(3). Calculate the work done on the gas.
Answer» Solution :`T = 27^(@)C = 27 + 273 = 300K, V_(1) = 10 dm^(3), V_(2) = 20 dm^(3)` `R = 8.314 J//K//mol` `W = -2.303 nRT log((V_(2))/(V_(1)))` `w = -2.303 xx 1 xx 8.314 xx 300 xx log((20)/(10))` `= -2.303 xx 8.314 xx 300 xx log 2` `= -2.303 xx 8.314 xx 300 xx 0.3010 = -1729 "joule" = -1.723 KJ`.