One mole of an ideal gas at 300 K expands from V to 2V volume, then work done W in this process will be …

One mole of an ideal gas at 300 K expands from V to 2V volume, then wo

1.	One mole of an ideal gas at 300 K expands from V to 2V volume, then work done W in this process will be …
Answer» 300 Rln2 600 Rln2 300n2 600ln2 Solution :WORK done in ISOTHERMAL process, `W=nRT ln (V_2/V_1)` n=1 , `V_2=2V_1`, T=300 K `thereforeW=Rxx300 ln ((2V_1)/V_1)` =300 Rln 2