One mole of an ideal gas at 300 Kin thermal contact with surroundings expandsisothermally from 1.0 L to 2.0 L against a constant pressure of 3.0 atm . In this process, the change in entropy of surroundings ( DeltaS_("surr") ) in JK^(-1)is( 1L atm = 101.3J )

One mole of an ideal gas at 300 Kin thermal contact with surroundings

1.	One mole of an ideal gas at 300 Kin thermal contact with surroundings expandsisothermally from 1.0 L to 2.0 L against a constant pressure of 3.0 atm . In this process, the change in entropy of surroundings ( DeltaS_("surr") ) in JK^(-1)is( 1L atm = 101.3J )
Answer» 5.763 1.013 `-1.013` `-5763` Solution :As the ideal gas undergoes isothermal EXPANSION. `DeltaU=0` As `q= DeltaU-W :. Q= - W` As gas EXPANDS against constant pressure. `W_("system") = - P DeltaV =- 3atm ( 2-1) L` `= - 3 L atm =- 3 xx101.3 J` `:. q_("system") = +3 xx 101.3 J` `q_("surr") = - q_("system") = - 3 xx 101.3J` `DeltaS_("surr.") = (q_("surr"))/(T) = ( - 3 xx 101.3J)/(300K) = -1.013J`