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One mole of an ideal gas expands isothermally and reversibles from 5 atmospheres to 1 atmosphere at 50^(@)C. Calculate the work done. |
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Answer» <P> SOLUTION :`T = 50^(@)C = 50 + 273 = 323 K, P_(1) = 5` atm, `P_(2) = 1` atm`R = 8.314 J//K//mol , n = 1` MOLE `W = -2.303 nRT log ((P_(1))/(P_(2))) = -2.303 xx 1 xx 8.314 xx 323 xx log((5)/(1))` `= -2.303 xx 1 xx 8.314 xx 323 xx 0.6990` `= -4,322.98 "joule" = -4.323 kJ` |
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