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One mole of an ideal gas undergoes a cyclic change ABCD where (P,V) co-ordinates are: A(5,1), B(5,3), C(2,3) and D(2,1). P is in atmosphere and V is in litre. Calculate the work done along AB, BC, CD, and DA and also net work done in the process. Given 1 atmosphere = 1.01xx10^(5)Nm^(-2) |
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Answer» `W_(1)= AREA ABFEA=EAxxEF` `=(5xx1.01xx10^(5))xx2xx10^(-3)= 1010J` (II) Work done along BC, `W_(2)= P(dV)= Zero` (III) Work done along CD, `W_(3)= -area CDEFC= -EDxxEF` `= -(2xx1.01xx10^(5))xx2xx10^(-3)= -404J` (iv) work done along DA, `W_(4)=P(dV)= Zero` Net work done in process `W=W_(1)+W_(2)+W_(3)+W(4)` `=1010+0-404+0= 606J` |
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