

InterviewSolution
Saved Bookmarks
1. |
One mole of any substance contains `6.022 xx 10^(23)` atoms/molecules. Number of molecules of `H_(2)SO_(4)` present in 100 mL of 0.02 M `H_(2)SO_(4)` solution is :A. `12.044 xx 10^(20)` moleculesB. `6.022 xx 10^(23)` moleculesC. `1 xx 10^(23)` moleculesD. `12.044 xx 10^(23)` molecules. |
Answer» Correct Answer - A Step I : Moles of `H_(2)SO_(4)(x)` `(0.02 mol_(L)^(-1))=(x)/((100//1000L))` `x=0.02xx0.1=0.002mol` Step II : Molecules of `H_(2)SO_(4)` `= 6.022 xx 10^(23) xx 0.002` `=12.044 xx 10^(20)` molecules. |
|