One mole of any substance contains 6.022xx10^(23)atoms/molecules. Number of molecules of H_(2)SO_(4)present in 100 mL of 0.02M H_(2)SO_(4) solution is ........ .

One mole of any substance contains 6.022xx10^(23)atoms/molecules. Numb

1.	One mole of any substance contains 6.022xx10^(23)atoms/molecules. Number of molecules of H_(2)SO_(4)present in 100 mL of 0.02M H_(2)SO_(4) solution is ........ .
Answer» `12.044xx10^(20)` molecules `6.022xx10^(23)` molecules `1xx10^(23)` molecules `12.044 xx 10^(23)` molecules Solution : One MOLE of any substance contains `6.022xx10^(23)` atoms/molecules. Hence, Number of MILLIMOLES of `H_(2)SO_(4)` `=` molarity `xx` volume in mL `= 0.02xx100 =2` millimoles `= 2 xx 10^(-3)` mol Number of molecules `= "number of moles" xx N_(A)` `= 2 xx 10^(-3) xx 6.022 xx 10^(23)` `= 12.044xx10^(20)` molecules