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One mole of `CaOCl_(2)` is dissolved in water andexcess of `KI` added. `Hypo(Na_(2)S_(2)O_(3))` required to react with the oxidised part completely isA. `1` moleB. `2.0` molesC. `1.5` molesD. `2.5` moles |
Answer» Correct Answer - B `underset(1 mol)(CaOCl_(2))+H_(2)O rarr Ca(OH)_(2)+underset(1 mol)(Cl_(2))` `Cl_(2)+2KI rarr 2KCl+underset(1 mol e)(I_(2))` `I_(2)+KI hArr KI_(3)` `I_(2)`(in `KI`) `+2Na_(2)S_(2)O_(3) rarr 2Nal+Na_(2)S_(4)O_(6)` |
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