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One mole of carbon-dioxide was found to occupy a volume of 1.32 litre at 48^(@) C and at a pressure of 16.4 atm. Calculate the pressure of the gas that would have been expected to behave ideally and non-ideally. |
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Answer» Solution :`[a = 3.59` atm `dm^(6) mol^(-2)], [b = 4.27 xx 10^(-2) dm^(3) mol^(-1)` and R = `0.082 dm^(3)` atm `DEG^(-1) mol^(-1)`] V = 1.32 lit T = `48 + 273 = 321 K` R = `0.082 dm^(3)` atm `K^(-1).mol^(-1)` (N = 1 mole) For ideal behaviour , PV = RT `P = (RT)/(V) = (0.082 xx 321)/(1.32)` `P_("ideal") = 19.94` atm For real behaviour , `P = (RT)/(V - b) - (a)/(V^(2))( n = 1 ` mole) For ideal behaviour , For ideal behaviour , `PV = RT` `P = (RT)/(V) = (0.082 xx 321)/(1.32)` ` P_("ideal") = 19.94` atm For real behaviour , `P = (RT)/(V -b) = (a)/(V^(2)) (n = 1`mole) `P = ((0.082 xx 321)/(1.32 - 0.0427)) - ((3.59)/((1.32)^(2)))` = `20.6 - 2.06` `P_("real") = 18.54` atm |
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