One mole of compound AB reacts with one mole of a compound CD according to the equation AB_((g)) + CD_((g)) hArr AD_((g)) + CB_((g)) . When equilibrium had been established it was found that 3/4 mole of reactants AB and CD had been converted to AD and CB . There is no change in volume . The equilibrium constant for the reaction is

One mole of compound AB reacts with one mole of a compound CD accordin

1.	One mole of compound AB reacts with one mole of a compound CD according to the equation AB_((g)) + CD_((g)) hArr AD_((g)) + CB_((g)) . When equilibrium had been established it was found that 3/4 mole of reactants AB and CD had been converted to AD and CB . There is no change in volume . The equilibrium constant for the reaction is
Answer» `9//16` `1//9` `16//9` 9 Answer :D