One mole of ethanol is produced reacting graphite, H_(2) and O_(2) together.The standard enthalpy of formation is -277.7 kJ mol^(-1).Calculate the standard enthalpy of the reaction when 4 moles of graphite is involved.

One mole of ethanol is produced reacting graphite, H_(2) and O_(2) tog

1.	One mole of ethanol is produced reacting graphite, H_(2) and O_(2) together.The standard enthalpy of formation is -277.7 kJ mol^(-1).Calculate the standard enthalpy of the reaction when 4 moles of graphite is involved.
Answer» `-277.7` `-555.4` `-138.85` `-69.42` Solution :`2C(s) + 1/2 O_(2)(g) + 3H_(2)(g) to C_(2)H_(5)OH(L)` `Delta_(f)H = -277.7 KJ"mol"^(-1)` Doubling the equation, `4C(s) +O_(2)(g) + 6H_(2)(g to 2C_(2)H_(5)OH(l)` `DeltaH = 2 xx (-277.7) = -555.4 kJ"mol"^(-1)`.