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One mole of fluorine is reacted with two moles of hot and concentrated KOH. The product formed are KF, `H_(2)O` and `O_(2)`. The molar ratio of `KF, H_(2)O` and `O_(2)` is respectivelyA. `1:1:2`B. `2:1:0.5`C. `1:2:1`D. `2:1:2` |
Answer» Correct Answer - B `F_(2)+2KOHto2KF+H_(2)O+1//2O_(2)` `:.` Molar ratio of `KF:H_(2):O_(2)` from balanced chemical equation is 2:1:0.5(1/2) |
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