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One mole of H_(2) and mole of I_(2) are allowed to attain equilibrium in 1 lit container . If the equilibrium mixture contains 0.4 mole of HI . Calculate the equilibrium constant . |
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Answer» Solution :GIVEN data : `[H_(2)] = 1` mole , `[I_(2)] = 1` mole At equilibrium , [HI] = 0.4 mole `K_(C)` = ? `H_(2) (G) + I_(2) (g) hArr 2HI (g)` `therefore "" K_(C) = ([HI]^(2))/([H_(2)] [I_(2)]) = (0.4 xx 0.4)/(0.8 xx 0.8) = 0.25` |
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