One mole of magnesium in the vapor state absored `1200 kJ mol^(-1)` of enegry. If the first and second ionization energies of `Mg` are `750` and `1450 kJ mol^(-1)`, respectively, the final composition of the mixture isA. `69% Mg^(+), 31% Mg^(2+)`B. `59% Mg^(+), 41% Mg^(2+)`C. `49%Mg^(+), 51% Mg^(2+)`D. `29% Mg^(+), 71% Mg^(2+)`

One mole of magnesium in the vapor state absored `1200 kJ mol^(-1)` of

1.	One mole of magnesium in the vapor state absored `1200 kJ mol^(-1)` of enegry. If the first and second ionization energies of `Mg` are `750` and `1450 kJ mol^(-1)`, respectively, the final composition of the mixture isA. `69% Mg^(+), 31% Mg^(2+)`B. `59% Mg^(+), 41% Mg^(2+)`C. `49%Mg^(+), 51% Mg^(2+)`D. `29% Mg^(+), 71% Mg^(2+)`
Answer» Correct Answer - A

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