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One mole of methanol when burnt in `O_(2)`, gives out 723 kJ `mol^(-1)` heat. If one mole of `O_(2)` is used, what will be the amount of heat evolvedA. 723 kJB. 924 kJC. 482 kJD. 241 kJ |
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Answer» Correct Answer - C `CH_(3)OH(l)+(3)/(2)O_(2)(g)rarrCO_(2)(g)+2H_(2)O(l) DeltaH=-723 kJ` By burning with `(3)/(2)O_(2)(g)` heat evolved =-723 kJ `therefore` By burning with 1 mole `O_(2)(g)=(-723xx2)/(3)=-482 kJ`. |
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