One mole of `N_(2)H_(4)` loses ten moles of electrons to form a new compound `A`. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in `A`? (There is no change in the oxidation state of hydrogen.)

One mole of `N_(2)H_(4)` loses ten moles of electrons to form a new co

1.	One mole of `N_(2)H_(4)` loses ten moles of electrons to form a new compound `A`. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in `A`? (There is no change in the oxidation state of hydrogen.)
Answer» Correct Answer - 3 `N_(2)H_(4)rarr(X)+10e` `because X` contains all `N`-atoms `:. (N^(2-))_(2)rarr(2N)^(a)+10e` Therefore `2a-(-4)=10 rArr a=+3`

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One mole of `N_(2)H_(4)` loses ten moles of electrons to form a new compound `A`. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in `A`? (There is no change in the oxidation state of hydrogen.)

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