One mole of nitrogen gas at 0.8 atm takes 38 s to diffuse through a pin hole whereas one mole of an unknown compound of Xenon with fluorine at 1.6 atm takes 57 s to diffuse through the same hole. Calculate the molecular formula of the compound.

One mole of nitrogen gas at 0.8 atm takes 38 s to diffuse through a pi

1.	One mole of nitrogen gas at 0.8 atm takes 38 s to diffuse through a pin hole whereas one mole of an unknown compound of Xenon with fluorine at 1.6 atm takes 57 s to diffuse through the same hole. Calculate the molecular formula of the compound.
Answer» Solution :Rate of diffusion `prop(P)/(sqrt(M)):. (r_(N_(2)))/(r_(X))=(P_(N_(2)))/(P_(X))xxsqrt((M_(X))/(M_(N_(2))))` But `r_(N_(2))=1//38" mol" s^(-1)` and `r_(X)=1//57" mol" s^(-1)` `:. (r_(N_(2)))/(r_(X))==(1//38)/(1//57)=(57)/(38)=(3)/(2)=(0.8)/(1.6)sqrt((M_(X))/(28))"or" sqrt(M_(X))=3xxsqrt(28)"or" M_(X)=9xx28=252` Atomic mass of F=19 u `"" :. ` No. of F-atmos`=(121)/(19)~-6` HENCE, the compound is `XeF_(6)`.