`6.022xx10^(23)` molecules of oxygen `6.022xx10^(23)` atoms of oxygen 16 G of oxygen 32 g of oxygen
Solution :At STP 1 MOLE of `O_(2)` gas`=6.022xx10^(23)`molecules of `O_(2)=32G` of `O_(2)` thus, 1 mole of oxygen gas is EQUAL to MOLECULAR weight of oxygen as well as Avogadro number.