One mole of P_(2)O_(5) undergoes hydrolysis as P_(2)O_(5) +H_(2)O to H_(3)PO_(4) The normality of the phosphoric acid formed is (Volume of the solution is 1L)

One mole of P_(2)O_(5) undergoes hydrolysis as P_(2)O_(5) +H_(2)O to

1.	One mole of P_(2)O_(5) undergoes hydrolysis as P_(2)O_(5) +H_(2)O to H_(3)PO_(4) The normality of the phosphoric acid formed is (Volume of the solution is 1L)
Answer» 2 12 24 Solution :b) `2P_(2)O_(5) + 6H_(2)O to 4H_(3)PO_(4)` `therefore` 1 L solution contains 4 moles of `H_(3)PO_(4)`. `therefore` molarity of `H_(3)PO_(4)` = 4M Normality = Molarity x Basicity = `4 xx 3N = 12N =10/10 xx 1000/100 = 2.5 m