One mole of PCI_(5) is heated in one litre closed container. If 0.6 mole of chlorine is found at equilibrium, calculate the value of equilibrium constant.

One mole of PCI_(5) is heated in one litre closed container. If 0.6 mo

1.	One mole of PCI_(5) is heated in one litre closed container. If 0.6 mole of chlorine is found at equilibrium, calculate the value of equilibrium constant.
Answer» Solution :`[PCl_(5)]_("initial")=(1 mol)/(1 DM^(3))` `[Cl_(2)]_(EQ)=0.6 mol dm^(-3)` `PCl_(5)harrPCl_(3)+Cl_(2)` `[PCl_(3)]_(eq)=0.6 "mole" dm^(-3)` `[PCl_(5)]_(eq)=0.4 "mole" dm^(-3)` `therefore K_(C)=([PCl_(3)][Cl_(2)])/([PCl_(5)])=(0.6xx0.6)/(0.4)` `K_(C)=0.9`