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One mole of PCl_5 is heated in one litre closed container. If 0.6 mole of chlorine is found at equilibium, calculate the value of equilibrium constant. |
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Answer» Solution :GIVEN that `[PCl_5]_("initial") = (1 mol)/(1 dm^3)` `[Cl_2]_(EQ) = 0.6 mol dm^(-3)` `PCl_5 HARR PCl_3 + Cl_2` `[PCl_3]_(aq) = 0.6 " mole" dm^(-3)` `[PCl_5]_(eq) = 0.4 " mole " dm^(-3)` `:. K_C =([PCl_3][Cl_2])/([PCl_5]) = (0.6 xx 0.6)/0.4` `K_C = 0.9` |
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