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One mole of PCl_(5) is heated in one litre closed container. If 0.6 mole of chlorine is found at equilibrium, calculate the value of equilibrium constant. |
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Answer» Solution :GIVEN that `[PCl_(5)]_("INITIAL")=("1 mole")/("1 DM"^(3))` `""[Cl_(2)]_(eq)=0.6" mol dm"^(-3)` `PCl_(5)hArrPCl_(3)+Cl_(2)` `[PCl_(3)]_(eq)=0.6" mole dm"^(-3)` `[PCl_(5)]_(eq)=0.4" mole dm"^(-3)` `:.K_(C)=([PCl_(3)][Cl_(2)])/([PCl_(5)])=(0.6xx0.6)/(0.4)` `K_(c)=0.9`. |
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