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One mole of PCl5 is heated in one litre closed container. If 0.6 mole of chlorine is found at equilibrium, calculate the value of equilibrium constant? |
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Answer» Given that [PCl5]initial = \(\frac{1 mol}{dm^3}\) [Cl2]eq = 0.6 mol dm-3 PCl5 ⇄ PCl3 + Cl2 [PCl5]eq = 0.6 mole dm-3 [PCl5]eq = 0.4 mole dm-3 ∴ KC = \(\frac{0.6 \times 0.6}{0.4}\) KC = 0.9 |
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