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One mole of symmetrical alkene upon ozonolysis gives two moles of an aldehyde having the molecular mass `44 u`. Predict the alkene.A. etheneB. propeneC. 1-buteneD. 2-butene.

Answer» Correct Answer - D
`C_(n)H_(2n)O=44rArrC_(n)H_(2n)=44-16=28`
`therefore` n = 2
Hence `CH_(3)-CH=CH-CH_(3)` is a symmetrical
`therefore underset("2-Butene")(CH_(3)-CH=CH-CH_(3))overset((i)O_(3))underset((ii)Zn//H_(2)O)rarrunderset("Acetaldehyde")(2CH_(3)-CH=O)`


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