One of the angles of a triangle is 100° and the other two angles are

1.	One of the angles of a triangle is 100° and the other two angles are equal. Find each of the equal angles.
Answer» Let the other two equal angles be x. Then, = x + x + 100^o = 180^o … [∵sum of the angles of a triangle is 180^o] = 2x = 180^o – 100^o = 2x = 80^o = x = 80^o/2 = x = 40^o Hence, the other two equal angles are 40^o and 40^o.

One of the angles of a triangle is 100° and the other two angles are equal. Find each of the equal angles.

Answer»

Let the other two equal angles be x.

Then,

= x + x + 100^o = 180^o … [∵sum of the angles of a triangle is 180^o]

= 2x = 180^o – 100^o

= 2x = 80^o

= x = 80^o/2

= x = 40^o

Hence, the other two equal angles are 40^o and 40^o.