InterviewSolution
Saved Bookmarks
| 1. |
One of the diagonals of a square is the portion of the line x/2+y/3=2 intercepted between the axes. Then the extremitites of the other diagonal are |
|
Answer» (5,5), (-1,1) `(x-2)/(3//SQRT(13)) = (y-3)/(2//sqrt(13)) =R` For the extremities of the diagonal, `r =+-sqrt(13).` Hence, `x-2 = +-3, y-3=+-2` x=5,-1 and y5,1 Therefore, the extremities of the diagonal are (5,5) and (-1,1). |
|