1.

One of the diagonals of a square is the portion of the line x/2+y/3=2 intercepted between the axes. Then the extremitites of the other diagonal are

Answer»

(5,5), (-1,1)
(0,0), (4,6)
(0,0),(-1,1)
(5,5),(4,6)

Solution :The extremities of the given DIAGONAL are (4,0) and (0,6) Hence, the slope of this diagonal is -3/2 and the slope of other diagonal is 2/3. The equation of the other diagonal is
`(x-2)/(3//SQRT(13)) = (y-3)/(2//sqrt(13)) =R`
For the extremities of the diagonal, `r =+-sqrt(13).` Hence,
`x-2 = +-3, y-3=+-2`
x=5,-1 and y5,1
Therefore, the extremities of the diagonal are (5,5) and (-1,1).


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