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One of the diagonals of a square is the portion of the line x/2+y/3=2 intercepted between the axes. Then the extremitites of the other diagonal areA. (5,5), (-1,1)B. (0,0), (4,6)C. (0,0),(-1,1)D. (5,5),(4,6) |
Answer» Correct Answer - A The extremities of the given diagonal are (4,0) and (0,6) Hence, the slope of this diagonal is -3/2 and the slope of other diagonal is 2/3. The equation of the other diagonal is `(x-2)/(3//sqrt(13)) = (y-3)/(2//sqrt(13)) =r` For the extremities of the diagonal, `r =+-sqrt(13).` Hence, `x-2 = +-3, y-3=+-2` x=5,-1 and y5,1 Therefore, the extremities of the diagonal are (5,5) and (-1,1). |
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