 
                 
                InterviewSolution
 Saved Bookmarks
    				| 1. | One plate of a capacitor is fixed, and the other is connected to a spring as shown in. Area of both the plates is `A` In strady state (equilibrium), separation between the plates is `0.8d` (spring was unstretched , and the distance between the plates was `d` when capacitor was uncharged). The force conntant of the spring is approximately. A. `(125)/(32) (epsilon_(0)AE^(2))/d^(3)`B. `(2epsilon_(0)AE^(2))/d^(3)`C. `(6epsilon_(0)E^(2))/(Ad^(2))`D. `(epsilon_(0)AE^(3))/(2d^(3))` | 
| Answer» Correct Answer - A `F=Kx` `Q^(2)/(2Aepsilon_(0))=K(0.2d)` or or `((epsilon_(0)A)/(0.8d)E)^(3)/(2Aepsi_(0))=0.2 Kd` or `K=3.9 epsilon_(0)AE^(2)//d^(3)` `K=4epsilon_(0)AE ^(2)//d^(3)`. | |