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One quarter sector is cut from a uniform circular disc of radius `R`. This sector has mass `M`. It is made to rotate about a line perpendicular to its plane and passing through the centre of the original disc. It moment of inertia about the axis of rotation is. .A. `(1)/(2) MR^(2)`B. `(1)/(4) MR^(2)`C. `(1)/(8) MR^(2)`D. `sqrt(2) MR^(2)` |
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Answer» Correct Answer - A Mass of the whole disc `= 4 M` Moment of inertia of the disc about the given axis. `(1)/(2) (4M) R^(2) = 2MR^(2)` :. Moment of inertia of quarter section of the disc. =`(1)/(4) (2MR^(2)) = (1)/(2) MR^(2)`. |
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