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One quarter sector is cut from a uniform circular disc of radius R. This sector has mass M. it is made to rotate about a line perpendicular to its plane and passing through the center of the original disc. Its moment of inertia about the axis of rotation is A. `(1)/(2)MR^(2)`B. `(1)/(4)MR^(2)`C. `(1)/(8)MR^(2)`D. `sqrt2MR^(2)` |
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Answer» For the complete disc, `M.I.` about the axis `=(1)/(2)(4M)R^(2)` For the quarter disc, `M.I.=(1)/(4)[(1)/(2)(4M)R^(2)]` `=(1)/(2)MR^(2)` |
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