one-thirdltd1. Divide 243 into three parts such that half of the first

1.	one-thirdltd1. Divide 243 into three parts such that half of the first part, one.second part and one-fourth of the third part are all equal.s The sum of the coins is e
Answer» Let first part be x, second part be y, third part 243 - (x + y) As per given condition x/2 = y/3 x = 2y/3....(1) Y/3 = [243 - ( x + y)] /4.....(2) Put Value of x from eq(1) in eq(2)4y/3 = 243 - (2y/3 +y)4y/3 + 5y/3 = 2439y/3 = 2433y = 243y = 81 x = 281/3 = 227 = 54 Three parts arex/2 = 54/2 = 27y/3 = 81/3 = 27[243 - (x + y)]/4 = (243 - 135) /4 = 108/4 = 27

one-thirdltd1. Divide 243 into three parts such that half of the first part, one.second part and one-fourth of the third part are all equal.s The sum of the coins is e

Answer»

Let first part be x, second part be y, third part 243 - (x + y)

As per given condition x/2 = y/3 x = 2y/3....(1)

Y/3 = [243 - ( x + y)] /4.....(2)

Put Value of x from eq(1) in eq(2)4y/3 = 243 - (2y/3 +y)4y/3 + 5y/3 = 2439y/3 = 2433y = 243y = 81

x = 2*81/3 = 2*27 = 54

Three parts arex/2 = 54/2 = 27y/3 = 81/3 = 27[243 - (x + y)]/4 = (243 - 135) /4 = 108/4 = 27