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One zero of the polynomial `3x^3+ 16x^2 + 15x -18` is `2/3.`Find the other zeroes of the polynomnial. |
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Answer» Here, `p(x) = 3x^3+16x^2+15x-18` One of the zero is `2/3`. `:. x = 2/3 = 0 => 3x-2 = 0` If we divide, `p(x)` by `3x-2`, we get, `x^2+6x+9`. `:. p(x) = (3x-2)(x^2+6x+9)` `= (3x-2)(x^2+3x+3x+9)` `= (3x-2)(x(x+3)+3(x+3))` `=>p(x)= (3x-2)(x+3)(x+3)` So, all the zeroes of `p(x)` are `2/3,-3,-3`. |
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