InterviewSolution
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| 1. |
\operatorname { s } \text { of } \left[ \begin{array} { r r r } { 7 } & { 2 } & { 2 } \\ { - 6 } & { - 1 } & { 2 } \\ { 6 } & { 2 } & { - 1 } \end{array} \right] |
| Answer» | |