\operatorname { sin } ^ { - 1 } ( \frac { 12 } { 13 } ) + \operatornam – InterviewSolution

1.	\operatorname { sin } ^ { - 1 } ( \frac { 12 } { 13 } ) + \operatorname { sec } ^ { - 1 } ( \frac { 13 } { x } ) = \frac { \pi } { 2 } \text { then } x =
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