\operatorname { tan } ^ { - 1 } ( \frac { 1 } { 4 } ) + \operatorname – InterviewSolution

InterviewSolution

1.	\operatorname { tan } ^ { - 1 } ( \frac { 1 } { 4 } ) + \operatorname { tan } ^ { - 1 } ( \frac { 2 } { 9 } ) = \frac { 1 } { 2 } \operatorname { tan } ^ { - 1 } \frac { 4 } { 3 }
Answer» and 1/2cos-1(3/5) = 1/2tan-1(4/3)

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