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( \operatorname { tan } 15 ^ { \circ } \times \operatorname { tan } 45 ^ { \circ } \times \operatorname { tan } 60 ^ { \circ } \times \operatorname { tan } 75 ^ { \circ } ) |
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Answer» tan15°= cot75°so it becomes =(cot75°×tan45°×tan60°×tan75°)::(cota × tana =1)= (1×1×root3)= root3 |
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