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ople 4 : In Fig. 9.22, ABeDIS IBE |I AC and also BE meets DC produced at Ethat area of Δ ADE is equal to the area of therilateral ABCDtion : Observe the figure carcfullyC and Δ EAC lie on the same base AC andeen the same parallels AC and BEefore, ar(BAC) - ar(EAC)r(BAC) + ar(ADC) = ar(EAC) + ar(ADC)Fig. 9.22(By Theor(Adding same areas on botar(ABCD) ar(ADE)EXERCISE 9.3. In Fig.9.23, E is any point on median AD of aA ABC. Show that ar (ABE)- ar (ACE).レ1n a triangle ABC, Eis the mid-point of medianAD: Show that ar (BED) ar(ABC)Show that the diagonals of a parallelogram divideit into four triangles of equal area.Fig. 9.23In Fig. 9.24, ABC and ABD are two triangles onthe same base AB. If line-segment CD is bisectedby AB at O, show that ar(ABC) ar (ABD).Fig. 9.24 |
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