1.

OR-5) is a root of the quadratic equation 2x2 px 15 0 and thequadratic equation pvalues of p and k.(x"x)k = 0 has equal roots, then find the+ts drawn from an external point to

Answer»

2x²+px-15=0x=-5 is root and it will satisfy the equation.2(-5)²+p(-5)-15=02(25)-5p-15=050-5p-15=035=5pp=7

Now the equation p(x²+x)+k=0 has equal roots.px²+px+k=0For equal root, b²=4ac

(-p)²=4(p)(k)p=7

(-7)²=4(7)(k)49=4*7*kk=7/4



Discussion

No Comment Found