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OR-5) is a root of the quadratic equation 2x2 px 15 0 and thequadratic equation pvalues of p and k.(x"x)k = 0 has equal roots, then find the+ts drawn from an external point to |
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Answer» 2x²+px-15=0x=-5 is root and it will satisfy the equation.2(-5)²+p(-5)-15=02(25)-5p-15=050-5p-15=035=5pp=7 Now the equation p(x²+x)+k=0 has equal roots.px²+px+k=0For equal root, b²=4ac (-p)²=4(p)(k)p=7 (-7)²=4(7)(k)49=4*7*kk=7/4 |
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