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or what value of k, does the given equationhave real and equal roots?(k + 1) x2 -2 (k 1) x 1 0. |
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Answer» For real and equal roots,Determinant = 0b^2 - 4ac = 04(k-1)^2 -4(k+1)=0k^2 + 1 - 2k - k -1=0k^2 - 3k=0k(k-3)=0k=0 and k=3 |
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