1.

Or• Prove that AB=0In figure, common tangents AB and CD to two circles intersect at E. Prove thathot

Answer»

Tangents to a circle from a common exterior point have equal lengths.

As AE and CE are tangents from common point E to the larger circle, AE = CE _______________(1)

As BE and DE are tangents from common point E to the smaller circle,BE = DE ______________(2)

By adding (1) and (2),AE + BE = CE + DEAB = CD

Hence proved



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