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ORDeepa deposits Rs. 1000 in first month. Rs.1450 inso on up to 5 years in a bank. Find the total amount that Deepa deposited at the end of 5yearssecond month. Rs. 1900 in third month and |
Answer» Deposit pattern forms an AP1000, 1450, 1900....... First term a = 1000, common difference d = 1450 - 1000 = 450 In 5 years total months are 12*5 = 60 Now sum of 60 terms of given AP = n/2(2a + (n-1)d)= 60/2(2*1000 + 59*450)= 30(2000 + 26550= 30(28550)= 856500 Therefore, total amount Deepa deposited in 5 years = Rs 85650 |
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