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Ordinary 'lead' pencils actually are made of a form of carbon called graphite. If a pencil line is `0.35 mm` wide and the diameter of a carbon atom is `1.5 xx 10^(-10)m`, how many `C` atom wide is the line?A. `2.3xx10^(6)`atomsB. `7.8xx10^(6)`atomsC. `5.6xx10^(6)`atomsD. `9.7xx10^(6)`atoms |
Answer» Correct Answer - A Number of `C` atoms `=("Width of the pencil line in meters")/("Diameter of a single "`C`" atom in meters")` `= 0.35mm xx (1m)/(1000mm)xx (1C "atom")/(1.5xx10^(-10)m)` `= 2.3 xx 10^(6)C` atoms |
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